Merge an array of size n into another array of size m+n
Merge an array of size n
into another array of size m+n
#include <stdio.h>
/* Assuming -1 is filled for the places where element
is not available */
/* Function to move m elements at the end of array mPlusN[] */
void moveToEnd(int mPlusN[], int size)
{
int i = 0, j = size
- 1;
for (i = size-1; i
>= 0; i--)
if (mPlusN[i] !=
NA)
{
mPlusN[j] =
mPlusN[i];
j--;
}
}
/* Merges array N[] of size n into array mPlusN[]
of size m+n*/
int merge(int mPlusN[], int N[], int m, int n)
{
int i = n; /* Current index of i/p part of mPlusN[]*/
int j = 0; /* Current index of
N[]*/
int k = 0; /* Current index of
of output mPlusN[]*/
while (k < (m+n))
{
/* Take an element from mPlusN[] if
a) value of the picked
element is smaller and we have
not reached end of
it
b) We have reached end
of N[] */
if ((i < (m+n)
&& mPlusN[i] <= N[j]) || (j == n))
{
mPlusN[k] =
mPlusN[i];
k++;
i++;
}
else // Otherwise take
element from N[]
{
mPlusN[k] =
N[j];
k++;
j++;
}
}
}
/* Utility that prints out an array on a line */
void printArray(int arr[], int size)
{
int i;
for (i=0; i <
size; i++)
printf("%d
", arr[i]);
printf("\n");
}
/* Driver function to test above functions */
int main()
{
/* Initialize arrays */
int mPlusN[] = {2,
8, NA, NA, NA, 13, NA, 15, 20};
int N[] = {5, 7, 9,
25};
int n =
sizeof(N)/sizeof(N[0]);
int m = sizeof(mPlusN)/sizeof(mPlusN[0])
- n;
/*Move the m elements at
the end of mPlusN*/
moveToEnd(mPlusN,
m+n);
/*Merge N[] into mPlusN[]
*/
merge(mPlusN, N, m,
n);
/* Print the
resultant mPlusN */
printArray(mPlusN,
m+n);
return 0;
}
Output:
2 5 7 8 9 13 15 20 25
Merge an array of size n into another array of size m+n
Reviewed by Unknown
on
August 24, 2018
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