Merge an array of size n into another array of size m+n


Merge an array of size n into another array of size m+n
#include <stdio.h>
/* Assuming -1 is filled for the places where element
   is not available */
/* Function to move m elements at the end of array mPlusN[] */
void moveToEnd(int mPlusN[], int size)
{
  int i = 0, j = size - 1;
  for (i = size-1; i >= 0; i--)
    if (mPlusN[i] != NA)
    {
      mPlusN[j] = mPlusN[i];
      j--;
    }
}
/* Merges array N[] of size n into array mPlusN[]
   of size m+n*/
int merge(int mPlusN[], int N[], int m, int n)
{
  int i = n;  /* Current index of i/p part of mPlusN[]*/
  int j = 0; /* Current index of N[]*/
  int k = 0; /* Current index of of output mPlusN[]*/
  while (k < (m+n))
  {
    /* Take an element from mPlusN[] if
       a) value of the picked element is smaller and we have
          not reached end of it
       b) We have reached end of N[] */
    if ((i < (m+n) && mPlusN[i] <= N[j]) || (j == n))
    {
      mPlusN[k] = mPlusN[i];
      k++;
      i++;
    }
else  // Otherwise take element from N[]
    {
      mPlusN[k] = N[j];
      k++;
      j++;
    }
  }
}
/* Utility that prints out an array on a line */
void printArray(int arr[], int size)
{
  int i;
  for (i=0; i < size; i++)
    printf("%d ", arr[i]);
  printf("\n");
}
/* Driver function to test above functions */
int main()
{
  /* Initialize arrays */
  int mPlusN[] = {2, 8, NA, NA, NA, 13, NA, 15, 20};
  int N[] = {5, 7, 9, 25};
  int n = sizeof(N)/sizeof(N[0]);
  int m = sizeof(mPlusN)/sizeof(mPlusN[0]) - n;
  /*Move the m elements at the end of mPlusN*/
  moveToEnd(mPlusN, m+n);
  /*Merge N[] into mPlusN[] */
  merge(mPlusN, N, m, n);
  /* Print the resultant mPlusN */
  printArray(mPlusN, m+n);
return 0;
}
Output:
2 5 7 8 9 13 15 20 25

Merge an array of size n into another array of size m+n Merge an array of size n into another array of size m+n Reviewed by Unknown on August 24, 2018 Rating: 5

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